Calculate the angle of the neutral axis from the x-axis

AI Thread Summary
To calculate the angle of the neutral axis from the x-axis for a beam loaded with a positive couple of 6 kNm, the equation tanθ = - (IxxMy - IxyMx)/(IyyMx - IxyMy) is used. The values for the moments of inertia are Ixx = 2854758.6 mm^4, Iyy = 1429034.6 mm^4, and Ixy = -1143476 mm^4, though some calculations suggest Ixy should be positive. There is confusion regarding the correct sign for Ixy and the maximum stress calculations, with discrepancies in results among users. Proper unit notation is emphasized, and users are encouraged to verify their calculations and share solutions for clarity. The discussion highlights the complexities of beam analysis under bending moments.
vtaela
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Homework Statement


Calculate the angle of the neutral axis from the x-axis when the beam is loaded with a positive couple of 6kNm acting around the X-axis



Homework Equations


i have calculated:
Ixx: 2854758.6 mm^4
Iyy: 1429034.6 mm^4
Ixy: -1143476 mm^4


The Attempt at a Solution



i know that to calculate the angle:

tanθ= - (IxxMy -IxyMx)/(IyyMx-IxyMy)

since i am confused with the statement "positive couple of 6kNm acting around the X-axis"

does that mean that Mx= 6KNm?

thank you
 
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Ya got any pictures of this problem?
 
ImageUploadedByPhysics Forums1363452818.241318.jpg


This is the the question
 
Mx is a couple which is acting as a bending moment on the cross section.
 
vtaela said:
Does that mean Mx = 6KNm?
That is correct.

(1) By the way, always leave a space between a numeric value and its following unit symbol. E.g., 6 kN, not 6kN. See the international standard for writing units[/color] (ISO 31-0[/color]).

(2) The unit symbol for kiloNewton is spelled kN, not KN. Capital K means kelvin.

(3) Two unit symbols multiplied together cannot be written together, and must be separated by, e.g., an asterisk or a space. E.g., kN*m or kN m, not kNm.
 
Last edited:
Thank u! I will have it in mind! In addition my ixy when i calculate it is positive and when i got the answer from solidworks i get a negative value! Which one is the correct?
 
vtaela: Although I have not tried it, it looks like Ixy perhaps should be positive. I do not know what SolidWorks is doing. Ensure your positive axes are pointing in the correct direction in SolidWorks.
 
Thank you very much
 
vtaela said:

Homework Equations


i have calculated:
Ixx: 2854758.6 mm^4
Iyy: 1429034.6 mm^4
Ixy: -1143476 mm^4

I got this except the Ixy was plus 1143476. Is this what you got when you did it again?
 
  • #10
Yes i calculates a positive ixy and a positive 38.66 degree
 
  • #11
When calculating the maximum stress did you use the unsymmetric bending equation? If you did what did you use as your x and y co-ordinates to input in that equation?
 
  • #12
X = -13.78 and y+= 38.11 getting a maximum stress of 136.7119
 
  • #13
How did you get them? Did you draw it out or is there a way to calculate them?
 
  • #14
Actually think i understand it.

X = Xc - bredth of rectangle 1
Y = height of rectangle 1 - Yc

That how you got them?
 
  • #15
Yes that's right
 
  • #16
Are you sure about your final stress value? I get 151.9855 N/mm^2 every time.

I've tried using hand calculations as well as using excel to double check the values and get that everytime.
 
  • #17
Take a picture of what you have done to compare the solution! I will reply tmr since i am not home now
 
  • #18
Heres my solution.
 

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  • #19
Same procedure except i used a positive Mx
 
  • #20
Any idea how to do question 1 of the coursework?:p
 
  • #21
Can you stick a pic of your solution up please. I completely missed the positive couple part in the question so can see where the positive mx comes from but now i now get -117.879 - 34.1061 = -151.99! Absolute nightmare haha.

Haha no idea, think everyone is stumped with that one.
 
  • #22
ImageUploadedByPhysics Forums1364731019.105529.jpg
 
  • #23
Cheers, i think you have your x and the y mixed up at the end. You have -3.09x + 2.475y when it should be -3.09y + 2.475x according to the equation?
 
  • #24
Yes you are right thank you for that
 
  • #25
No problem
 
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