Calculate the avg speed for the ENTIRE trip.

  • Thread starter Thread starter physicsnobrain
  • Start date Start date
  • Tags Tags
    Speed
Click For Summary

Homework Help Overview

The problem involves calculating the average speed of a car traveling from school to home and back, with specific speeds for each segment of the trip and a total time given. The context revolves around understanding average speed versus average velocity in a round trip scenario.

Discussion Character

  • Conceptual clarification, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants explore the implications of the term "entire trip" and whether it refers to a round trip or just one way. There are discussions on calculating total distance and total time, as well as the distinction between average speed and average velocity.

Discussion Status

The discussion is ongoing, with participants questioning assumptions about the trip's direction and the interpretation of the total time provided. Some guidance has been offered regarding the calculation method, emphasizing the need to consider total distance and total time.

Contextual Notes

There is uncertainty regarding the completeness of the problem statement and whether the trip includes a return journey. Participants are also reflecting on the definitions of average speed and average velocity in the context of the problem.

physicsnobrain
Messages
123
Reaction score
0

Homework Statement


A car travels to home from school. For the first 100km it travels 100km/h and for the rest of trip travels 50km/hr and completes the trip in 1 hr and 42 min. Calculate the avg speed for the ENTIRE trip.

Homework Equations


Average Speed=∑i|d/Δttotal

The Attempt at a Solution


It's asking for the entire trip so we assume it comes back home.

In this case is avg speed = 0 because the displacement was 0.
 
Last edited:
Physics news on Phys.org
It looks like an incomplete text. Is this the actual text or a "summary"?
 
nasu said:
It looks like an incomplete text. Is this the actual text or a "summary"?

I'm just wondering if it is correct
 
Aha, you modified the text.
Now it makes sense. And you can calculate the average speed.
The trip is exactly what they say: from school to home.
Calculate the total distance traveled and divide by the total time.
It may some room for interpretation when they say "completes the trip in 1 h and 42 min".
He did the first 100 km (in 1h) and then it takes another 1h 42min to finish the trip?
Or he completed the whole trip in 1 h and 42 min, which will leave 42 min for the portion traveled with 50 km/h.
 
so what I said is wrong? We have to assume they came from home to school. The actual question bolds the words "entire trip"
 
physicsnobrain said:
so what I said is wrong? We have to assume they came from home to school. The actual question bolds the words "entire trip"
No, this is not a valid assumption. No info is given for the home to school trip. And besides, average velocity and average speed are not the same when traveling round trip. By the ENTIRE trip it means both sections of the one way trip from school to home.
 
so then the avg speed would be 75 km/h
 
Average speed is not the average of the two speeds. You need to use the formula you wrote yourself. Total distance/total time.
 
nasu said:
Average speed is not the average of the two speeds. You need to use the formula you wrote yourself. Total distance/total time.

Forgive me guys, this was a test question I'm just going off memory. But a friend told me that it said the person drove from home.

So then the entire trip would be to the school and back.


If this is the case, then is the avg speed 0m/s?
 
  • #10
physicsnobrain said:
Forgive me guys, this was a test question I'm just going off memory. But a friend told me that it said the person drove from home.

So then the entire trip would be to the school and back.


If this is the case, then is the avg speed 0m/s?
If the person drove from home to school and back to home, the average velocity (total displacement divided by total time) would be 0. Average speed is total distance traveled divided by total time.
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
4K
Replies
5
Views
3K
  • · Replies 10 ·
Replies
10
Views
8K
  • · Replies 6 ·
Replies
6
Views
3K
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
Replies
40
Views
7K
  • · Replies 3 ·
Replies
3
Views
1K