Calculate the avg speed for the ENTIRE trip.

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The discussion revolves around calculating the average speed for a car trip from school to home, with the car traveling 100 km at 100 km/h and then 50 km/h for the remainder of the trip, completing it in 1 hour and 42 minutes. There is confusion regarding whether the trip includes a return journey, with some participants suggesting that if it does, the average speed could be zero due to zero displacement. However, the correct interpretation is that the average speed should be calculated based on total distance traveled divided by total time, leading to an average speed of 75 km/h. Clarifications emphasize that average speed and average velocity are distinct concepts, particularly in round trips. The conversation highlights the importance of precise wording in problem statements for accurate calculations.
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Homework Statement


A car travels to home from school. For the first 100km it travels 100km/h and for the rest of trip travels 50km/hr and completes the trip in 1 hr and 42 min. Calculate the avg speed for the ENTIRE trip.

Homework Equations


Average Speed=∑i|d/Δttotal

The Attempt at a Solution


It's asking for the entire trip so we assume it comes back home.

In this case is avg speed = 0 because the displacement was 0.
 
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It looks like an incomplete text. Is this the actual text or a "summary"?
 
nasu said:
It looks like an incomplete text. Is this the actual text or a "summary"?

I'm just wondering if it is correct
 
Aha, you modified the text.
Now it makes sense. And you can calculate the average speed.
The trip is exactly what they say: from school to home.
Calculate the total distance traveled and divide by the total time.
It may some room for interpretation when they say "completes the trip in 1 h and 42 min".
He did the first 100 km (in 1h) and then it takes another 1h 42min to finish the trip?
Or he completed the whole trip in 1 h and 42 min, which will leave 42 min for the portion traveled with 50 km/h.
 
so what I said is wrong? We have to assume they came from home to school. The actual question bolds the words "entire trip"
 
physicsnobrain said:
so what I said is wrong? We have to assume they came from home to school. The actual question bolds the words "entire trip"
No, this is not a valid assumption. No info is given for the home to school trip. And besides, average velocity and average speed are not the same when traveling round trip. By the ENTIRE trip it means both sections of the one way trip from school to home.
 
so then the avg speed would be 75 km/h
 
Average speed is not the average of the two speeds. You need to use the formula you wrote yourself. Total distance/total time.
 
nasu said:
Average speed is not the average of the two speeds. You need to use the formula you wrote yourself. Total distance/total time.

Forgive me guys, this was a test question I'm just going off memory. But a friend told me that it said the person drove from home.

So then the entire trip would be to the school and back.


If this is the case, then is the avg speed 0m/s?
 
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physicsnobrain said:
Forgive me guys, this was a test question I'm just going off memory. But a friend told me that it said the person drove from home.

So then the entire trip would be to the school and back.


If this is the case, then is the avg speed 0m/s?
If the person drove from home to school and back to home, the average velocity (total displacement divided by total time) would be 0. Average speed is total distance traveled divided by total time.
 
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