Calculate the coefficient of friction on a rotating carnival ride

AI Thread Summary
To calculate the minimum coefficient of static friction for a person on a rotating carnival ride, the relevant equations include the frictional force being less than or equal to the normal force multiplied by the coefficient of friction. Given a radius of 5.5 meters and a rotation frequency of 0.50 revolutions per second, the coefficient of static friction can be determined using the formula us = g/(T*r). The calculation yields a coefficient of static friction of approximately 0.891. Additionally, the centripetal acceleration is provided by the normal force, which is crucial for preventing slipping. Understanding the forces at play is essential for solving this problem accurately.
kevinlmoses
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Homework Statement


In a "rotor-ride" at a carnival, people rotate in a vertical cylindrically walled room. If the room radius was 5.5m, and the rotation frequency 0.50 revolutions per second when the floor drops out, what minimum coefficient of static friction keeps the people from slipping down?


Homework Equations


F(friction)</= usF(normal)
F(normal)=mg
us=g/(T*r)

The Attempt at a Solution


us=g/(T*r)
us=9.8/(2*5.5)
us=.891
 
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Draw a free body Diagram of a person on the ride. The normal force between the person and the wall of the ride is what is providing the centripetal acceleration (directed towards the center of the ride).
Force of Gravity acts down on the person and so friction acts up on the person to keep them from falling.

Looking at the vertical components (of the forces) we know that Fg = Ff in order to keep the person from falling.
Solve for normal force by finding the centripetal force required at the given speed.

Once you know normal force and Force of Friction you can then use the following equation to solve for the coefficient of friction.
Ff(Friction) = N(normal force) x Coefficient of Friction
 
kevinlmoses said:

Homework Statement


In a "rotor-ride" at a carnival, people rotate in a vertical cylindrically walled room. If the room radius was 5.5m, and the rotation frequency 0.50 revolutions per second when the floor drops out, what minimum coefficient of static friction keeps the people from slipping down?

Homework Equations


F(friction)</= usF(normal)
F(normal)=mg
us=g/(T*r)

The Attempt at a Solution


us=g/(T*r)
us=9.8/(2*5.5)

Welcome to PF.

I'm not sure where you are getting these equations. But that said I'm not seeing your answer in terms of π .

w = 2*π*f = v/r
 
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