Calculate the equilibrium concentration of hydrogen ions

Click For Summary

Discussion Overview

The discussion centers around calculating the equilibrium concentration of hydrogen ions in a chemical reaction, specifically using the ICE table method. The context appears to be homework-related, focusing on stoichiometry and the dissociation of an acid.

Discussion Character

  • Homework-related
  • Mathematical reasoning

Main Points Raised

  • One participant suggests applying the ICE table method directly to the problem, indicating that it is essential for determining the concentrations of the substances involved.
  • Another participant expresses confusion despite receiving a link to a resource, indicating that further clarification may be needed.
  • A participant emphasizes the importance of identifying the acid (HA) and its conjugate base (A-) in the dissociation reaction to understand the stoichiometric relationships.
  • It is proposed that expressing the concentrations of HA, H+, and A- in terms of one unknown, preferably H+, is a strategic approach to solve for pH.

Areas of Agreement / Disagreement

Participants do not appear to reach a consensus, as one expresses confusion and seeks further clarification while another provides guidance on the method to use.

Contextual Notes

The discussion may be limited by the participants' varying levels of understanding of the ICE table method and the specific details of the dissociation reaction involved.

fender1984
Messages
2
Reaction score
0

Homework Statement

 
Last edited:
Physics news on Phys.org
Thank you for the link Borek but I'm still lost
 
You have to directly apply the ICE table method to your case.

What is your HA? A-?

Basically it is about stoichiometry - from the dissociation reaction you can easily see that for each mole/molecule of A- (H+) produced, one mole/molecule of HA is consumed. You just have to express concentrations of all three substances involved (HA, H+, A-) in terms of one unknown - best approach is to use H+ as the unknown, as you are asked about pH.
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
Replies
4
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 5 ·
Replies
5
Views
5K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
5K
  • · Replies 7 ·
Replies
7
Views
2K