# Calculate the force exerted on the handle of a wheelbarrow

1. Sep 3, 2009

### flin8812

1. The problem statement, all variables and given/known data

The total weight of a wheel barrow filled with gravel=240N
Wheelbarrow held on an 18 degree incline
Other dimesions are given as in the figure provided.

2. Relevant equations
Assuming that the wheelbarrow is at static equilibrium,

3. The attempt at a solution

my attempt of part(a) was to have the total moment=0
where F represents the uplifting force

Mc=($$\overline{CB}$$)(F)-(rxFy)(ryFx)

= $$\sqrt{1.01^2+0.8^2}$$(0.2*240cos15)+(0.58*240sin18)

=0
but I don't know what to do next....
1. The problem statement, all variables and given/known data

2. Relevant equations

3. The attempt at a solution

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2. Sep 3, 2009

### method_man

Try to calculate:
$$\sum x=0$$
$$\sum y=0$$
$$\sum M=0$$
I sketched some forces on your picture. I would calculate moment around C.

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