Calculate the maximum height that m1 and m2 rise after collision?

AI Thread Summary
To calculate the maximum height that blocks m1 and m2 rise after their elastic collision, first determine the speed of m1 as it falls through the quarter circle from point A to B. This can be achieved by applying energy conservation principles, where the potential energy at point A is converted to kinetic energy at point B. After finding m1's velocity, use the conservation of momentum during the collision at point B to find the velocities of both blocks post-collision. Finally, apply energy conservation again to calculate the maximum height each block reaches after the collision. The solution involves understanding the dynamics of elastic collisions and energy transformations in a frictionless environment.
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Homework Statement


Consider a frictionless track. Imagine point A to B is one quarter of a circle; point B to C is a horizontal flat plane; point C to D is also one quarter of a circle.

The block m1 is released from A. It makes a head-on elastic collision at B with m2 (that is initially at rest) Calculate the maximum height to which m1 and m2 rise after collision.

m1 = 2kg
m2 = 10 kg
radius of quarter circles = 4.9 m


Homework Equations


p=mv

m1vf + m2vi = (m1 + m2)v

y=1/2 at^2


The Attempt at a Solution


I am not quite sure how to attempt a solution.
 
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Can you find out how fast m1 is going after it falls through the quarter of a circle A to B? Then you could do conservation of momentum on the collision at B.
 
I understand the equation for conservation of momentum, but how do I go about finding the velocity as you mentioned?
 
Draw the diagram. You should see how high above the BC horizontal section m1 is initially. From the initial height, you can calculate its speed after falling through the height either by using forces or energies.
 
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