Calculate the moment of inertia

AI Thread Summary
To find the moment of inertia (I) of the axle in the given problem, the relationship between tension (T), angular acceleration (α), and linear acceleration (a) is crucial. The equations of motion, such as S = 0.5at^2 and v = at, can be utilized to derive necessary variables. The connection between linear and angular quantities, specifically v = rω, allows for the conversion of linear motion into angular motion. The discussion emphasizes using energy principles and Newton's second law to simplify the problem. Overall, a systematic approach combining kinematics and dynamics will lead to the correct expression for I in terms of m, r, t, and S.
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Homework Statement


A mass m is tied with a light string,which it's another end is winded at a axle fixed at wall,in which it's radius is r.
Assume there is no friction.The mass is released from rest and falls a distance S after time t.
Find the moment of inertia of the axle.(represents I in terms of m,r,t and S)

Homework Equations


work done by moment=0.5Iω^2
v=at
S=0.5at^2

The Attempt at a Solution


my final equation is as follows
TS=0.5Iω^2,where T is the tension
v=at=rαt where α is the angular acceleration
(mg-T)S=0.5mv^2
but i can't reach the requirement
maybe there are lots of error inside and sorry for my poor english
 
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Try solving for v and ω.
 
A mass m is tied with a light string,which it's another end is winded at a axle fixed at wall,in which it's radius is r.
Assume there is no friction.The mass is released from rest and falls a distance S after time t.
Find the moment of inertia of the axle.(represents I in terms of m,r,t and S)
well let's look at what's happening...
You have a mass on an axel, and you release it, the Earth (gravity) exerts a torque of ##T = I\dot{\omega}## on the axel and it accelerates angularly at a rate of ##\dot{\omega}##

So I guess what it boils down to is this: how else can you define ##T##?
There's another definition that involves 2 things that you are given (variables) and a constant that you know.

Answer this and we'll go from there.

PS I like this problem =]
 
There are several ways to solve this. There is nothing wrong with the original approach using work and energy. The only thing to realize is that v and ω are not unknowns--a little kinematics is all you need to find them.
 
i almost forgot i can use the formula v^2-u^2=2as
so v=sqrt(2rαS) ?
and ω=αt or ω=v/R
am i going right?
 
what's u?
Also you're over complicating it in my opinion.
Start out with what you know, write out some definitions, and when in doubt: N2L is god.
 
asdff529 said:
i almost forgot i can use the formula v^2-u^2=2as
so v=sqrt(2rαS) ?
and ω=αt or ω=v/R
am i going right?
First step is to find the acceleration. You had the formula in your first post.
asdff529 said:
S=0.5at^2

Then find v. Again, you had the formula in your first post.
asdff529 said:
v=at

Given v, you can find ω since they are related.

Then you can use the energy equations you wrote in your first post.
 
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