Calculate the rate of energy output of the sun, taking the sun as a blackbody

AI Thread Summary
The discussion focuses on calculating the sun's energy output using its surface temperature of approximately 5800K and radius of 6.96x10^8m, applying the blackbody radiation formula H = εσAT^4. A participant initially misinterprets the question, calculating energy per unit area instead of total power output. The correct approach involves using the total surface area of the sun to determine the overall energy output in watts. Clarifications highlight the importance of distinguishing between radius and Stefan-Boltzmann constant in the calculations. Accurate calculations are essential for understanding the sun's total energy output.
ninaw21
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1. The surface temperature of the sun is approximately 5800K. Given that the radius of the sun is 6.96x108m calculate the rate of energy output of the sun, taking the sun as a blackbody.

2. H = εσAT4



3. Surface temp = 5800K, Radius of the sun = 6.96x108, Emissivity of a blackbody = 1
H = εσAT4
H/A = (1)(6.96x108)(5800)4
= 7.87x1023W/M2

Am I right??
 
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No. Question is asking for "the rate of energy output" which is power (watts). You also seem to be confusing radius with σ, Stephan's constant.
 
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