Calculate the Rate of Increase for Doubling Radius of an Ink Spot

  • Thread starter Thread starter Procrastinate
  • Start date Start date
  • Tags Tags
    increase Rate
Click For Summary
SUMMARY

The radius of a circular ink spot, defined by the equation r=(1+4t)/(2+t), doubles from its initial value of 1/2 at a specific time. The correct rate of increase at this moment is 7/9 cm/s, while the incorrect calculation yielding 9/7 cm/s does not align with the problem's conditions. The confusion arises from misinterpreting the time at which the radius doubles, as the rate of change at t=1 does not meet the criteria set by the problem statement.

PREREQUISITES
  • Understanding of calculus, specifically derivatives and rates of change.
  • Familiarity with circular geometry and the properties of circles.
  • Ability to manipulate algebraic expressions and solve equations.
  • Knowledge of limits and continuity in mathematical functions.
NEXT STEPS
  • Study the concept of derivatives in calculus to understand rates of change.
  • Explore the application of the chain rule in related rates problems.
  • Learn about the geometric interpretation of derivatives in circular motion.
  • Investigate how to apply limits to analyze behavior at specific points in functions.
USEFUL FOR

Students and professionals in mathematics, physics, and engineering who are dealing with problems involving rates of change and circular motion dynamics.

Procrastinate
Messages
155
Reaction score
0
The radius of a circular ink spot, t seconds after it first appears, is given by:

[tex]r=\frac{1+4t}{2+t}[/tex]

Find the rate of increase (in cm/s) at the time when th radius as doubled from its initial value.



I have attached my working; however, the answer is 7/9cm/s and I keep getting 9/7cm/s. Does that even make sense if it is doubling anyways?
 

Attachments

  • scan0014.jpg
    scan0014.jpg
    27.1 KB · Views: 407
Physics news on Phys.org
I don't see any problem with your work; it seems to me that 9/7 is right. 7/9 is the rate of change at t=1, but that doesn't correspond to the condition given in the problem, since the initial radius is 1/2 and the radius at t = 1 is 5/3.
 

Similar threads

Replies
3
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
5
Views
3K
  • · Replies 30 ·
2
Replies
30
Views
4K
  • · Replies 15 ·
Replies
15
Views
3K
  • · Replies 5 ·
Replies
5
Views
6K
  • · Replies 54 ·
2
Replies
54
Views
5K
  • · Replies 30 ·
2
Replies
30
Views
2K
Replies
6
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K