Calculate the resistance at 18 Celsius

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To calculate the resistance of a copper coil at 18 Celsius, the formula R = ρL/A is used, where ρ is the resistivity of copper, L is the total length of the wire, and A is the cross-sectional area. The resistivity of copper and its temperature coefficient are essential for determining resistance at different temperatures, including 100 Celsius. Resources like chemistry or electrical engineering reference books can provide necessary values, or a quick online search can yield helpful information. New users are encouraged to post questions in designated homework forums for better assistance. Understanding these calculations is crucial for accurately determining resistance in electrical applications.
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cant do this question, well i can't figure out what I am supposed to do, whether its a thermistor or not, i worked out the inductance, but I am not sure what to do after that, here's the question

Calculate the resistance at 18 celcius of a 5cm diameter close-wound, single layer coil of 1000 turns of copper wire of 0.1mm diameter.

what would its approximate resistance be at a temperature of 100 celcius?

thanks
 
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Doesn't sound like they want the inductance -- sounds like they are asking for the resistance of the coil at two different temperatures. You need the rho of copper, and it's tempco (temperature coefficient). The total resistance R = rho*L/A, where L = total length, and A = area (of the wire cross-section in your case).

If you have a chem table book or EE reference book handy, you can find the info in there. Or easier is to just google the following:

+copper +resistivity +temperature

and the first hit you get will give you what you need:

http://hypertextbook.com/facts/2004/BridgetRitter.shtml

BTW, I'm kind of a newbie to the PF forums, so I just learned recently that questions like this are supposed to be posted in the HW forums. So now I try to check out the HW question forums to see if I can be of help.
 
thanks that's very helpful, i jus joined the forums, that was my first post, so i haven't a clue what is going on in here anyways, cheers
 
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