Calculate the resultant thrust and overturning moment

AI Thread Summary
To calculate the retaining force needed to keep a vertical retaining gate shut against water pressure, the hydrostatic pressure formula (P = D*g*h) and the thrust force equation (Thrust force = D*g*(h/2)*A) are essential. The gate dimensions are clarified as 2 meters wide and 24 meters high, with the thickness being negligible for this calculation. The overturning moment can be determined using the thrust force and the height of the gate. There is some confusion regarding the gate's dimensions and the need for a diagram, but the focus remains on calculating the torque due to water pressure. Understanding these principles is crucial for solving the problem effectively.
Taidhg
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Homework Statement


A vertical retaining gate 2metres X 24metres hinged about the bottom edge of a dry dock has water to a depth of 21 metres on one side. Calculate the Retaining Force at the middle of the free upper edge of the gate to keep it shut in the vertical position. With the density of seawater being 1030Kg/m3.

Homework Equations


Hydrostatic pressure = D*g*h
Force = P*A
Thrust force = D*g*(h/2)*A
Overturning moment = Thrustforce*(h/3)

The Attempt at a Solution


I am sorry I really don't understand this question.
 
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upload_2018-12-9_9-33-10.png


Is this a picture of the problem? It seems to me that the weight and density of the gate is needed?
 

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Spinnor said:
View attachment 235477

Is this a picture of the problem?
I wasn't provided with a diagram however that is the same as the one I produced
 
Taidhg said:
I wasn't provided with a diagram however that is the same as the one I produced

I thought the thickness of the gate was 2m. The height I guess is 2 meters, the width is 24, and the gates thickness is small. You need to integrate the total torque on the gate and equate that with 2xF ?

I would be wrong. The height must be 24m and the width 2m which makes for a very tall and narrow gate. Now I'm confused also.
 
The gate is 2 meters in width, 24 meters high, and its thickness is irrelevant. Think about how you might calculate the torque about the hinge's axis due to the water pressure.

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gneill said:
and its thickness is irrelevant

If it is thick then its weight might contribute a torque. But that info was not given.
 
Spinnor said:
If it is thick then its weight might contribute a torque. But that info was not given.
Place the hinge in the center of the door thickness. Problem solved :smile:

upload_2018-12-9_12-29-5.png
 

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