Calculate the weight of the satellite on the surface of the Earth

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SUMMARY

The discussion focuses on calculating the weight of a communications satellite with a mass of 340 kg on the surface of the Earth and the gravitational force exerted on it while in orbit. The mass of the Earth is given as 5.97x1024 kg, and the radius of the Earth is 6,356,908.8 m. The gravitational force was calculated using the formula Fg = G(m1*m2)/r2, resulting in a force of 294.4 N, which converts to 0.2944 kN. The discussion clarifies that the distance in Newton's Law of Gravitation should be measured from the center of the Earth, not the surface.

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  • Ability to convert units (e.g., from Newtons to kilonewtons)
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This discussion is beneficial for physics students, aerospace engineers, and anyone interested in gravitational physics and satellite dynamics.

SoccaCrazy24
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A communications satellite with a mass of 340 kg is in a circular orbit about the Earth. The radius of the orbit is 27800 km as measured from the center of the Earth.
(a) Calculate the weight of the satellite on the surface of the Earth.
(b) Calculate the gravitational force exerted on the satellite by the Earth when it is in orbit.

Well here are some information needed for the problem...
Mass of Earth = 5.97x10^24 kg
Radius of Earth = 6,356,908.8 m

I already have a...
But for b.. I used the equation Fg= G(m1*m2)/r^2
so... Fg = (6.67x10^-11 * 340 * 5.97^24)/(27800000-6356908.8)^2 = 294.4 N is this right? because it asks for it in kN which is .2944 kN did i do something wrong somewhere because somehow that isn't right...
 
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The distance in Newton's Law of Gravitation is from the center of mass of the two objects involved. In this case, it'll be essentially from the center of the Earth, not from the surface.
 
thanks diane...
 

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