Calculate Torque Needed to Spin an LP Turntable 648 Degrees

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To calculate the torque needed for an LP turntable to reach an angular speed of 3.51 rad/s in 1.8 revolutions (648 degrees), one must first convert the revolutions to radians, resulting in 11.3097 rad. The discussion emphasizes the importance of using rotational kinematics equations, which are analogous to linear kinematics, to relate angular displacement, angular velocity, and angular acceleration. Key equations include the rotational analog of Newton's second law, Torque = I * alpha, and the moment of inertia for a uniform disk, I = 0.5 * m * r^2. By applying these equations, one can determine the necessary torque for the turntable's motor. Understanding these principles is crucial for solving the problem effectively.
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An LP turntable must spin at 3.51 rad/s to play a record. How much torque must the motor deliver if the turntable is to reach its final angular speed in 1.8 revolutions, starting from rest? The turntable is a uniform disk of diameter 31 cm and mass 0.26 kg.

I know that 1.8rev is equal to 648 degrees. This means that the disc must spin 648 degrees to reach the required 3.51 rad/s for the record.

But I don't know how to begin to calculate the torque required to achieve that angular velocity. Where do I begin> Thanks
 
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mikefitz said:
An LP turntable must spin at 3.51 rad/s to play a record. How much torque must the motor deliver if the turntable is to reach its final angular speed in 1.8 revolutions, starting from rest? The turntable is a uniform disk of diameter 31 cm and mass 0.26 kg.

I know that 1.8rev is equal to 648 degrees. This means that the disc must spin 648 degrees to reach the required 3.51 rad/s for the record.

But I don't know how to begin to calculate the torque required to achieve that angular velocity. Where do I begin> Thanks
Begin by expressing everything in radians rather than degrees, and by reviewing the equations of rotational kinematics. They are directly analogous to liner kinematics.
 
so, total rotation (1.8 rev) is equal to 11.3097 rad. It must spin at 3.51 rad/s.

How do I use this information to calculate a torque? thanks again
 
mikefitz said:
so, total rotation (1.8 rev) is equal to 11.3097 rad. It must spin at 3.51 rad/s.

How do I use this information to calculate a torque? thanks again
Look at your rotational kinematics equations. Find one that relates a change in angular velocity to an angular displacement and a constant angular acceleration. Find another one that relates torque to angular acceleration.

There are other paths to the solution (ther usually are) but these two equations will be a fairly direct route.
 
equations my teacher has given me:

KErot = .5 I w^2
I = .5 m r^2
Torque = F r sin(theta)

I guess I am unsure which equation relates all these different elements together?
 
mikefitz said:
equations my teacher has given me:

KErot = .5 I w^2
I = .5 m r^2
Torque = F r sin(theta)

I guess I am unsure which equation relates all these different elements together?
Look here and scroll down to the table showing the linear equations and their angular analogs.

http://online.cctt.org/physicslab/content/PhyAPC/lessonnotes/rotationalmotion/kinematics.asp

You should have seen all of these before. If you have not ssen them, you are seeing them now. Give particular attention to the last one. There is also a rotational analog of Newton's second law

F=ma <> Torque = I*alpha

See what you can do with these.
 
great, thanks for the help OlderDan - no I had not seen that last equation until I clicked your link.
 
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