Calculate useful energy output ?

[Neil1985]

I have a problem i am trying to solve, the question is;
Calculate the velocity ratio for this system. If the work put in is 3000J, calculate the useful energy output.
The system in question is a Hydraulic lifting frame upon which crates are placed.
It is lifted with a hydraulic ram which is located between the load and the fulcrum, thus making this system the third order of lever.
The distance from the load to the effort is 5M and the distance from the effort to the fulcrum is 1M.

LOAD--------(5M)------I---(1M)---o (pivot)

I = Hydraulic ram.


(i apologize for the poor diagram!) Thank you in advance for any help.

 

[mitch_1211]

If the work put in is 3000J, calculate the useful energy output.

The distance from the load to the effort is 5M and the distance from the effort to the fulcrum is 1M.

LOAD--------(5M)------I---(1M)---o (pivot)

I = Hydraulic ram.

Using F_effort = F_load * d_load/d_effort and solving for F_load we get F_load = F_effort * d_e/d_l

and subbing in the distances and applied (effort) force we get
F_load = 3000J * 1/6 = 500J so you be able to lift masses up to about 50kg