Calculate Work Done by Field to Remove 5µC Charge from Equilateral Triangle

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To calculate the work done by the electric field when removing a 5µC charge from an equilateral triangle configuration, one must first determine the electric potential at the location of the charge due to the other charges. The potential is influenced by the two remaining charges, which are -5µC and 10µC, positioned at specific distances. The relationship between work done and electric potential is given by the equation W = q(V), where W is work, q is the charge being removed, and V is the potential at that point. To find the potential, the contributions from each charge must be calculated using the formula for electric potential due to a point charge. Understanding these concepts is crucial for solving the problem effectively.
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Homework Statement


I built a configuration of charge on an equilateral triangle with side length of 10cm shown
below. I decided however that I have one to many charges and wish to remove the 5μC charge completely. How much work is done by the field when I remove the charge?

The triangle has a -5µC up top then a 10µC on bottom left and finally a 5µC on the bottom right. Thanks for any help


Homework Equations





The Attempt at a Solution



I have no idea where to begin, thanks for any help.
 
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Do you know the relation between work done and potential ?
And how to find the potential of a charge at a given distance?
 
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