Calculating 3D Component Vectors and Resultant Force for Inclined Forces

AI Thread Summary
The discussion focuses on calculating the component vectors and resultant force for two forces acting in three dimensions. Force F2 is directed along the negative z-axis with a magnitude of 130N, while force F1 has a magnitude of 80N and is inclined at angles of 40 degrees from the positive x-axis and 50 degrees from the negative y-axis, with a 30-degree incline on the z-axis. Participants clarify the method for determining the z-component of the forces, emphasizing the importance of correctly interpreting the angles in relation to the axes. The conversation highlights the need to project the forces onto the xy-plane to accurately calculate the resultant force. Understanding these vector components is essential for sketching the resultant vector in the coordinate system.
yhumei
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Express each force as a Cartesian vector and then determine the resultant force F. Find the magnitude and coordinate direction angles of the resultant force and sketch this vector on th coordinate system.
There's a drawing of 1 force(F2) of magnitude 130N, along the negative z direction(-z), and another force(F1) of magnitude 80N, 40 degrees from the +x direction, 50 degrees from the -y direction and an incline of 30 degrees on the +z direction.




I want to know the component vectors of this force



I know how to find the component vectors of the forces using the x-axis direction and the y-axis directions only, I don't know the way to find the component vectors for the z-axis. (Which I think are (80sin40i and 80cos40j) if I am wrong please correct me.)
 
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Hi yuhumei and welcome to PF. Consider a plane defined by the z-axis and the vector. Draw your vector assuming that the paper is that plane. Can you find its z-component?
 
you're mis-interpreting the diagram ...
If those angles were really from the vector itself straight to each axis,
then (cos^2 + cos^2 + cos^2) has to = 1.
Probably, the "projection" of the 80N force onto the xy plane is 50deg from -y and 40deg from +x ... and the vector is 30deg from z .
 
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