Calculating AC and DC Resistance of a Silicon Diode in 300K

AI Thread Summary
The discussion focuses on calculating the AC and DC resistances of a silicon diode at 300K, given a saturation current of 2µA and a forward current of 20mA. The AC resistance is derived as 1.3 ohms through differentiation of the diode current equation. For DC resistance, the formula DC(resistance) = V(forward)/I(forward) is used, with participants attempting to determine the forward voltage to finalize their calculations. One participant calculated the DC resistance as approximately 11.9 ohms, which was confirmed by another as being close to 11.97 ohms. The conversation highlights the importance of verifying calculations and understanding diode behavior in circuit analysis.
rclakmal
Messages
76
Reaction score
0
Diode ac and dc resistance?

here is my question ...saturation current of a silicon diode is 2uA.and forward current is 20mA...i want to find out the AC and DC resistances of the diode in 300k...

so i know that ,

I(forward)=I(saturate)[exp(eV/nKT)-1]

..so by differentiating both sides w.r.t to V i got that dI/dV=I(forward)*e/nkt...here KT/e=26mv so by subbing than (and also n=1 when conducting through diode)i got dV/dI=1.3ohms ...
so that is Ac resistance of the diode ...
but i don't know how to find the DC resistance of the diode can anyone help me out
 
Physics news on Phys.org


Are you sure that differentiation is right? doesn't look correct.
 


i think its correct ...what i have done is after differentiation i have subb i(forward) to the term I(saturation)*exp(ev/nKT)...and I am sure of that because i have done it before ...but i don't know how to calculate DC resistance ...DC(resistance)=V/I ...am i correct ...but i don't how to get a value for that ...
 


Yea sorry its correct. I thought doing that gave DC resistance not AC. Also do you know the foward voltage.
 


No i don't ,,,,,,,,,but after referring to some of my books i got some idea ...though i don't have the forward voltage i might be able to calculate it using forward and reverse currents by subbing them in the above equation then can get forward voltage ...

so i think DC(resistance)=V(forward)/I(forward)...
 


can someone check this answer for me ......here i forward is 20mA i saturated is 2uA and temp is 300k....i got the answer as R(dc)=11.9 ohms ...am i correct ?please someone check and tell me because in the MCQ question there is no such answer .....:(
 


I'll ask my teacher. That sounds a bit high though.
 


rclakmal said:
can someone check this answer for me ......here i forward is 20mA i saturated is 2uA and temp is 300k....i got the answer as R(dc)=11.9 ohms ...am i correct ?please someone check and tell me because in the MCQ question there is no such answer .....:(

I calculated 11.97 ohms which agrees well enough with your answer.
 


Thnaks dude !it was a great help!
 
Back
Top