Calculating Acceleration and Distance: Entering the Freeway

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A car accelerates from rest on a 115 m ramp to reach a speed of 30 m/s, achieving an acceleration of 3.91 m/s² and taking approximately 7.61 seconds to complete the ramp. The discussion focuses on calculating the distance traveled by freeway traffic during this time, with initial calculations yielding incorrect results. The correct approach involves using the formula for distance at constant velocity, which is distance equals velocity multiplied by time. The freeway traffic, moving at 30 m/s, covers a distance of 229.8 m during the car's ramp traversal. Accurate understanding of constant velocity and proper application of the distance formula are crucial for solving this problem.
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Entering the Freeway. A car sits in an entrance ramp to a freeway, waiting for a break in the traffic. The driver sees a small gap between a van and an 18-wheel truck and accelerates with constant acceleration along the ramp and onto the freeway. The car starts from rest, moves in a straight line, and has a speed of 30 m/s (67 mi/h) when it reaches the end of the 115 m long ramp.

Ok for the acceleration I got 3.91 m/s/s and got that it takes 7.61 s for the car to travel the length of the ramp, but I don't understand part C:

(c) The traffic on the freeway is moving at a constant speed of 30 m/s. What distance does the traffic travel while the car is moving the length of the ramp?

i got 117.4 m but idk
 
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Musicman said:
Ok for the acceleration I got 3.91 m/s/s and got that it takes 7.61 s for the car to travel the length of the ramp.
These are both correct, however I think you have induced a rounding error, the time should be 7.67s
Musicman said:
(c) The traffic on the freeway is moving at a constant speed of 30 m/s. What distance does the traffic travel while the car is moving the length of the ramp?

i got 117.4 m but idk
I'm afraid this is not correct. Don't forget the traffic is traveling at a constant velocity.
 
what did u get then? because I am totally lost like i knew what i was doing for the first 2 parts but not this part.
 
Musicman said:
what did u get then? because I am totally lost like i knew what i was doing for the first 2 parts but not this part.
I'm not giving you the answer :-p . Think about traveling at constant velocity. What is the equation for uniform velocity? How do you define velocity?
 
x=v of x times t
 
Musicman said:
x=v of x times t
Thats right, distance is equal to the product of velocity and time. Use it:wink:
 
well i put 29.75 and it said its wrong and it was my last submission so oh well, apparently 7.61 times 3.91 doesn't work.
 
Musicman said:
well i put 29.75 and it said its wrong and it was my last submission so oh well, apparently 7.61 times 3.91 doesn't work.
3.91 is the acceleration of the car traveling up the ramp not the velocity of the cars traveling on the freeway which would be 7.66 x 30 = 230m
 
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