Calculating Acceleration and Net Force of a Moving Block | Homework Question

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To calculate the acceleration of the block, the correct formula to use is d = Vi*t + 0.5*a*t², rather than v = d/t, which is only applicable for constant velocity. Given the distance of 3.0m and time of 6 seconds, the acceleration is determined to be 0.083 m/s². The net force acting on the block, calculated using Fnet = Ma, results in 0.664N when using the correct acceleration value. It is crucial to apply the appropriate equations for accelerated motion to obtain accurate results. Proper application of physics principles is essential for solving such problems effectively.
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Homework Statement


A block of mass 8.0kg starting from rest is pulled along a rough horizontal tabletop by a constant force of 2N it is found that the block moves a distance of 3.0m in 6 seconds
a) what is the acceleration?
b) What is the net force acting on the block?

Homework Equations


Fnet = Ma



The Attempt at a Solution


v = d/t
v = 3/6
v = 0.5m/s
a = v/t
a = 0.08m/s^2
Fnet = 8 x 0.08
= 0.64N [F]
 
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You can't use v = d/t when the motion is accelerated.
Use formulas with acceleration in them.
d = Vi*t + .5*a*t² should work well.
 

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