Calculating Acceleration and Tension in a Pulley System on an Inclined Plane

  • Thread starter Thread starter squintyeyes
  • Start date Start date
  • Tags Tags
    Desperate Physics
AI Thread Summary
A mass on a frictionless incline is connected to a pulley, and the problem involves calculating the acceleration of the mass, the angular acceleration of the pulley, and the tension in the string. The incline angle is 42.0°, and the mass is 3.00 kg, with the pulley having a moment of inertia of 0.400 kgm² and a radius of 0.145 m. The user calculated the linear acceleration as 0.8931 m/s² and the angular acceleration as 6.1599 rad/s², with tension calculated at 17 N. However, the user faced issues with their answers being marked wrong, prompting a request for verification of their calculations and clarification on significant figures and constants. The discussion highlights the importance of careful arithmetic and adherence to problem specifications for accurate results.
squintyeyes
Messages
44
Reaction score
0
A mass is placed on a frictionless incline and attached to a pulley by a light string. The situation is sketched below.



The incline angle, theta, is 42.0°, the mass is 3.00 kg, the moment of inertia of the pulley is 0.400 kgm2 and the radius of the pulley is 0.145 m. The mass is released from rest.

(a) What is the magnitude of the acceleration of the mass?
___________m/s2
(b) What is the magnitude of the angular acceleration of the pulley?
___________rad/s2
(c) What is the tension in the string?
___________ N


Attempt
T =tension in the string which opposes mass
weight perpendicular to ramp = mgsinθ
a= linear acceleration
mgsinθ-T=ma

Iα=T*r(Because force on pulley is tension T and distance from center of pulley is r)

α=a/r

T=Iα/r=Ia/r2

substituting in
mgsinθ-Ia/r2=ma
mgsinθ=a(m+I/r2)
a=mgsinθ/(m+I/r2)=0.8931m/s2

b)α=0.9/0.145=6.1599rad/s2
c)T=Ia/r2=0.4*0.9/(0.145)2=17N

can someone who knows what they are doing look this over and fix any mistakes.
Please i really need this.
 

Attachments

  • rotation picture.jpg
    rotation picture.jpg
    3.8 KB · Views: 466
Physics news on Phys.org
That seems ok to me.
 
Welcome to PF!

Hi squintyeyes! Welcome to PF! :wink:

(I haven't checked your arithmetic :redface:, but apart from that I agree with Dick) your formulas are fine. :smile:
 
but my answers are marked wrong and i am down to my last try
 
(just got up :zzz: …)
squintyeyes said:
but my answers are marked wrong and i am down to my last try

hmm … it would have helped if you'd said that at the start. :redface:

well, I've looked at it again, including the arithmetic, and I can't see what's wrong.

Which parts are marked right, and which wrong?

How many sig figs are you supposed to enter? how many did you enter?

Are you supposed to use g = 9.8 or 9.81?

Are you sure it says "radius", not "diameter"?
 
Thanks for looking at this. I plugged the first two answers to three decimal places and got them both wrong and it says radius not diameter. I am lost. Thanks again
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top