Calculating Activation Energy and Rate Constant for a Chemical Reaction

  • Thread starter Thread starter kittymaniac84
  • Start date Start date
  • Tags Tags
    Activation Energy
AI Thread Summary
The discussion focuses on calculating the activation energy and rate constant for the reaction 2NOCI (g) = 2NO (g) + Cl2 (g) using the Arrhenius equation. The provided rate constants at two temperatures (350 K and 400 K) allow for the determination of the activation energy (Ea) and the pre-exponential factor (A). One participant initially expressed confusion about applying the Arrhenius equation but later confirmed their calculations. The final results indicated an activation energy of 100,232 J/mol and a rate constant of 4.06 x 10^-3 Is at 425 K. The calculations appear to be verified and correct.
kittymaniac84
Messages
17
Reaction score
0
[SOLVED] Activation energy

The reaction, 2NOCI (g) = 2NO (g) + Cl^{}_2{}(g) , has rate constant values for the reaction of NOCl of 9.3 x 10^-6 Is at 350 K and 6.9 x 10^-4 Is at 400 K. Calculate the activation energy for the reaction. What is the rate constant at 425 K?

I am unsure how to solve this. Can someone help me and show me how to do it.
 
Physics news on Phys.org
SCREAMS arrhenius equation.
 
Excuse me, why the rude behavior? This is suppose to be a help forum. It might be obvious to you, but I'm not sure if I am using the equation right.
 
The Arrhenius equation is ln(k) = ln(A) - E/(RT). You are given values of k at two different temperatures T. R is the gas constant, A and E are empirical constants, E being the activation energy. So just plug the corresponding values (k,T) into this equation to generate two equations in two unknowns. After you know A and E, use the equation to get k at any other T. Does this help?
 
Yes thank you. I already figured this out on my own. That is exactly what I did. Ea=100,232, A=8.47x10^9, and with T=425 I got 4.06x10^-3 for k.

I hope i did the math right but it looks right.
 
Thread 'Confusion regarding a chemical kinetics problem'
TL;DR Summary: cannot find out error in solution proposed. [![question with rate laws][1]][1] Now the rate law for the reaction (i.e reaction rate) can be written as: $$ R= k[N_2O_5] $$ my main question is, WHAT is this reaction equal to? what I mean here is, whether $$k[N_2O_5]= -d[N_2O_5]/dt$$ or is it $$k[N_2O_5]= -1/2 \frac{d}{dt} [N_2O_5] $$ ? The latter seems to be more apt, as the reaction rate must be -1/2 (disappearance rate of N2O5), which adheres to the stoichiometry of the...
Back
Top