Calculating Angle of Fuzzy Dice with Acceleration

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To calculate the angle of fuzzy dice hanging from a rearview mirror during acceleration, the forces acting on the dice must be analyzed. The downward gravitational force (Mg) and the tension force (T) must be resolved into their components, with the horizontal component equal to the mass times acceleration (M(3.54 m/s^2)) and the vertical component balancing the weight (Tsin(theta) = Mg). The equations Tcos(theta) = M(3.54 m/s^2) and Tsin(theta) - Mg = 0 are essential for finding the angle theta. The discussion highlights the need for proper application of trigonometric relationships to derive the angle from the tension components. Understanding these force dynamics is crucial for solving the problem accurately.
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I'm not sure I have enough info but the question goes like this...Fuzzy dice are hanging from a rearview mirror. The car accelerates at 3.54m/s^2 What angle will the dice make with the vertical? I have a force diagram showing of the dice Mg points down. T points up to the right in the 1st quadrant. For the summation of forces I have Fx=Tcos(theta)=M(3.54m/s^2) and Fy=Tsin(Theta)-Mg=0. What am I missing? Not sure how to find theta..Thanks
 
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Thanks but why does that work. (Where is the Homework forum?)[?] [?]
 
Ambi,

Do me a favor and try using some of the LaTeX code! :)

- Warren
 

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