Calculating Angle of Fuzzy Dice with Acceleration

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The discussion centers on calculating the angle of fuzzy dice hanging from a rearview mirror when a car accelerates at 3.54 m/s². The participant outlines a force diagram where the gravitational force (Mg) acts downward and the tension (T) acts at an angle (theta) in the first quadrant. The equations provided include Fx = Tcos(theta) = M(3.54 m/s²) and Fy = Tsin(theta) - Mg = 0. The participant seeks clarification on how to solve for theta, indicating a need for further understanding of the relationship between tension and acceleration.

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Kharmon7814
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I'm not sure I have enough info but the question goes like this...Fuzzy dice are hanging from a rearview mirror. The car accelerates at 3.54m/s^2 What angle will the dice make with the vertical? I have a force diagram showing of the dice Mg points down. T points up to the right in the 1st quadrant. For the summation of forces I have Fx=Tcos(theta)=M(3.54m/s^2) and Fy=Tsin(Theta)-Mg=0. What am I missing? Not sure how to find theta..Thanks
 
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Thanks but why does that work. (Where is the Homework forum?)[?] [?]
 
Ambi,

Do me a favor and try using some of the LaTeX code! :)

- Warren
 

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