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Gulheider
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A torque of 70 N-m acts for 10s on a disk with moment of inertia 160kg*m^2. If the disk is originally stationary, what's final angular speed of the disk?
Calculating Angular Speed: 70 N-m Torque on a 160kg*m^2 Disk for 10s
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A torque of 70 N-m is applied for 10 seconds to a stationary disk with a moment of inertia of 160 kg*m^2. The final angular speed can be calculated using the formula τ = I * α, where α is the angular acceleration. By rearranging the equation, the angular acceleration can be determined, and then the final angular speed can be found using the relationship ω = α * t. The discussion emphasizes the importance of following homework guidelines and suggests checking specific equations related to rotational dynamics for clarity. The final angular speed of the disk can be accurately calculated using these principles.
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19.
For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Here we know that if block B is going to move up or just be at the verge of moving up
##Mg \sin \theta ## will act downwards and maximum static friction will act downwards ## \mu Mg \cos \theta ##
Now what im confused by is how will we know " how quickly" block B reaches its maximum static friction value without any numbers, the suggested solution says that when block A is at its maximum extension, then block B will start to move up but with a certain set of values couldn't block A reach...
Figure 1 Overall Structure Diagram
Figure 2: Top view of the piston when it is cylindrical
A circular opening is created at a height of 5 meters above the water surface. Inside this opening is a sleeve-type piston with a cross-sectional area of 1 square meter. The piston is pulled to the right at a constant speed. The pulling force is（Figure 2）： F = ρshg = 1000 × 1 × 5 × 10 = 50,000 N.
Figure 3: Modifying the structure to incorporate a fixed internal piston
When I modify the piston...
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