Calculating Average Velocity of Dropped Bolt From High-Rise Building

AI Thread Summary
To calculate the average velocity of a dropped bolt from a height of 320 meters, the position function is given as s(t) = 320 - 5t^2 for the interval 0 <= t <= 8. The average velocity over the interval from t = 3 to t = 8 is found using the formula Δs/Δt, resulting in a value of 55 m/s. However, it is noted that the negative sign should be retained to indicate the downward direction of the velocity. Therefore, the correct average velocity is -55 m/s. This emphasizes the importance of direction in velocity calculations.
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Homework Statement



A construction worker drops a bolt while working on a high-rise building 320m above the ground. After t seconds, the bolt has fallen a distance of s metres, where s(t) = 320-5t^2, 0 <= t <=8

Find the average velocity for the interval 3<=y<=8

Homework Equations





The Attempt at a Solution



I used the formulas \Deltas / \Deltat
which then =
s(8) - s(3) / (8-3)

~
~
=55

Is this right?
 
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The magnitude is correct but I think you want to keep the negative sign to indicate direction.
 

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