Calculating Ball Diameter in a Beaker: Accounting for Tension and Buoyancy

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To determine the diameter of a submerged Ping-Pong ball in a beaker, the tension in the thread and the buoyant force must be considered. The tension in the thread equals the buoyant force, which is derived from Archimedes' principle stating it equals the weight of the fluid displaced. The calculations involve determining the mass of the displaced fluid and subsequently the volume of the ball. An error in the initial approach was identified, highlighting the need to account for both tension and gravitational forces acting on the ball. Correctly applying these principles will lead to the accurate calculation of the ball's diameter.
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Ball in a Beaker - Diameter - Please Help!

Homework Statement



A thread attaches a 2.73-g Ping-Pong ball to the bottom of a beaker. When the beaker is filled with water so that the ball is totally submerged, the tension in the thread is 6.75 mN. Determine the diameter of the ball.

Homework Equations



r = [6(T + mg)/π × 10^3g]^1/3

The Attempt at a Solution



I am using the above equation but cannot get the right answer!
 
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The equation is not correct. Try to derive the formula for the diameter yourself.

ehild
 


ehild is correct, you need to derive the equation yourself. I would recommend thinking about the force diagram first. Which forces are pulling the ping pong ball down? Which forces are pulling it up? They have to be equal and opposite to each other if the ball isn't accellerating.
 


A thread attaches a 2.74-g Ping-Pong ball to the bottom of a beaker. When the beaker is filled with water so that the ball is totally submerged, the tension in the thread is 6.87 mN. Determine the diameter of the ball.

The force pushing the ping pong ball up is the buoyant force of the water. Thus if the force pulling it down is equal, the tension is equal to the buoyant force. According to Archimedes principal, the buoyant force on a object immersed in fluid is equal to the weigh of the fluid displaced by that object. So the weight of the fluid displaced is 6.87 mn. Thus, the mass is 0.00687 N / 9.87 N = 0.000701 kg. Then, d = m*v. D of water is 1000 kg * m^3. Solving for volume, we get the volume as 7.0102 * 10^-7 m^3. Then we solve for volume with (x/2)^3 * pi * 4/3 = 7.0102 * 10^-7 m^3. I get x to = 0.011022 m. But this is not the answer; what am I doing wrong?
 


tak08810 said:
The force pushing the ping pong ball up is the buoyant force of the water. Thus if the force pulling it down is equal, the tension is equal to the buoyant force.
You are forgetting about another force that acts on the ball.
 


Redbelly98 said:
You are forgetting about another force that acts on the ball.

Ah thank you! So tension + gravity is the force going down and the buoyant force opposes it.
 
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