Calculating Ball's Initial Speed: All Gravitational Energy

AI Thread Summary
To calculate the initial speed of a ball thrown to a height of 2.2 meters, one can use the kinematic equation v^2 = u^2 + 2as, where v is the final velocity at the peak (0 m/s), a is the acceleration due to gravity, and s is the height. The discussion highlights the importance of understanding whether to apply energy conservation principles or kinematic equations, depending on the context of the problem. It also notes the ambiguity in the question regarding the starting height of the ball, which could affect the solution. Clarifying the assumptions made about the initial height is crucial for accurate calculations. Overall, the problem serves as a basic physics exercise in understanding motion and energy.
jamescutmore
Messages
1
Reaction score
0
Acceleration -- all the energy is gravitational what speed was the ball thrown at?

Homework Statement


A ball is thrown up in the air and reaches a height of 2.2m assuming that all the energy is gravitational what speed was the ball thrown at.


Homework Equations


I cannot find the equation


The Attempt at a Solution


??any help would be appreciated
 
Physics news on Phys.org


1. Well you are given the height it reaches. You also know the acceleration due to gravity. Finally you know the velocity of the ball at maximum height. So you know Smax, a and v. You want to find u (the initial velocity)

2. You must use the relevant 'SUVAT' equation.
You can use v^2=u^2 +2as
..to rearrange to find u.

Hope that helps.
p.s. Just to let you know, I'm from the UK, am not sure if they teach it the same in the US assuming you are in the US? but i suspect this applies universally.
 
welcome to pf!

hi james! welcome to pf! :smile:

as a matter of interest: since this is an energy question, why have you titled it "acceleration" ? :confused:

anyway, show us your energy equations :smile:
 


He doesn't know about conservation of energy yet. This is a week-one physics problem meant to be solved using the one-dimensional motion equations.

The equations you're looking for are at the bottom of this page.

http://www.physicsclassroom.com/class/1dkin/u1l6a.cfm

edit: then again, the question does mention energy so maybe I'm wrong.
 


This is a very poorly worded question, because it doesn't tell you from what height the ball is thrown. It could have started at -713 meters for example. Most people will presuppose a beginning point of 0 meters. But you have to be careful making that presupposition since it could result in a wrong answer in other problems (whereas in this problem is just makes it solvable). You should probably explicitly state the assumption that the ball begins at 0 meters.

And it's been brought up, but let me ask you directly: What are you learning in your class right now (or in what context are you working this problem [it may not be for a class])? Depending on that context, the approach to help you changes. As others have said, it matters if you (should) know conservation of energy or if you're working with kinematic equations.
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanged mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...

Similar threads

Back
Top