Calculating Black Particle Size in a Red Giant Solar System - Astronomy Homework

AI Thread Summary
The discussion focuses on calculating the size of black spherical particles in a future red giant solar system, where the Sun's brightness increases significantly while its mass decreases. Participants clarify that the light force on the particles must equal the gravitational force to determine the critical size for ejection from the solar system. Key variables include the radius of the particle (a), the energy received (Q), and the flux of sunlight. The gravitational force and light force equations are set to be equal, but there is confusion regarding the definitions and calculations of these variables. Overall, the thread seeks guidance on correctly setting up the problem to find the particle size.
Jeann25
Messages
30
Reaction score
0

Homework Statement


When the Sun becomes a red giant star its brightness will increase by a factor of 5000 and its mass will decrease to half of its present mass. When this happens particles smaller than a critical size will be blown out (light force = gravity force) of the solar system by the pressure of sunlight. What is the size for a black spherical particles ( they absorb all light that falls on them) with density of 1000 kg/m^3.

Homework Equations



radiation force on a spherical particle=F=((flux)*π a^2 Q)/c

The Attempt at a Solution



So in the problem it says that the light force = grav force
((flux)*π a^2 Q)/c = GMm/r^2 = GM/r^2 * (4π a^3 ρ)/3
(from example in book)
But I don't know what a, Q or flux is. I would estimate r= 1AU.
This also wouldn't use the change in brightness.
Need some help on where to go with this problem because I think I'm setting this up all wrong :(
 
Last edited:
Physics news on Phys.org
Since the attractive gravitational force and the amount of light hitting the particle both drop off as r^2 they cancel - the effect is the same at any distance.

a looks like the radius of the particle.
Q is normally the energy received.

You need an equation for
1, the attractive force of gravity on a particle of mass m
2, the force of light on an area A
3, the equation for the mass and cross section area of a sphere of a given radius and density.
Then you just set equations 1 and 2 equal.
 
Thread 'Confusion regarding a chemical kinetics problem'
TL;DR Summary: cannot find out error in solution proposed. [![question with rate laws][1]][1] Now the rate law for the reaction (i.e reaction rate) can be written as: $$ R= k[N_2O_5] $$ my main question is, WHAT is this reaction equal to? what I mean here is, whether $$k[N_2O_5]= -d[N_2O_5]/dt$$ or is it $$k[N_2O_5]= -1/2 \frac{d}{dt} [N_2O_5] $$ ? The latter seems to be more apt, as the reaction rate must be -1/2 (disappearance rate of N2O5), which adheres to the stoichiometry of the...
Back
Top