- #1

just wonderin

- 2

- 0

take a glass of water and place a straw in it. Now put oil in the staw.

the amount of oil above the water is given by the equation.

ex)

density of oil=d1(.5)

density of water d2(1)

height of oil column = H(10")

d1/d2 x H = amount of oil under water line(x) x=5"

H-x= amount above(p)p=5"

now say (p) is one fluid ounce " it is in a vertical column". if you changed the shape of the column above the water line would (p) still have to be the same height to push the oil to a depth of (x)? Or is it the mass of the water above to the water below what counts.

I have tried this with wood and the shape of the above part dosent mater. the bottom part always sinks to the same depth.as long as the ratio top/bottom is the same. is this true for liquids?

the amount of oil above the water is given by the equation.

ex)

density of oil=d1(.5)

density of water d2(1)

height of oil column = H(10")

d1/d2 x H = amount of oil under water line(x) x=5"

H-x= amount above(p)p=5"

now say (p) is one fluid ounce " it is in a vertical column". if you changed the shape of the column above the water line would (p) still have to be the same height to push the oil to a depth of (x)? Or is it the mass of the water above to the water below what counts.

I have tried this with wood and the shape of the above part dosent mater. the bottom part always sinks to the same depth.as long as the ratio top/bottom is the same. is this true for liquids?