Calculating Charge and Acceleration of Two Charged Spheres

AI Thread Summary
To calculate the number of electrons needed to accelerate two charged spheres at 15.0 g, the forces acting on the spheres were set equal using the equations F=ma and F=k(q1q2/r^2). The mass of each sphere is 8.55 g, and the distance between them is 20.0 cm. The calculation led to a charge Q of approximately 2.39e-4 C, which was then converted to the number of electrons using the charge of a single electron (1.6e-19 C). This resulted in a total of about 1.49e15 electrons required for each sphere. The discussion clarified the correct interpretation of acceleration and distance in the calculations.
Josh930
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Homework Statement



Two very small 8.55-g spheres, 20.0cm apart from center to center, are charged by adding equal numbers of electrons to each of them.

Disregarding all other forces, how many electrons would you have to add to each sphere so that the two spheres will accelerate at 15.0 g when released?

Homework Equations



F=ma
F=k(q1q2/r^2)
q=ne



The Attempt at a Solution



for one.. i don't know why the acceleration is at 15.0 g?

But i did try to set the forces equal and solve q, then plugged q into the equation q=ne and it wasn't right.

Please help
 
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Show your calculations.
 
F=ma=F=k(q1q2/r^2)

q1=q2; let Q^2=q1q2

sqrt(mar^2/k)=Q

sqrt((8.55g*15.0m/s)((2m)^2)/k)=Q

Q=2.39e-4

Q=ne

n=2.39e-4/1.6e-19

=1.49e15 electrons
 
The acceleration is 15*g i.e. 15*9.8 m/s^2
In the solution you have written (2m)^2. What is that?
 
they are 20cm apart? so .2m
 
i messed up and wrote 2m. so 15g is 15x the acceleration of gravity
 
Yes.
 
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