- #1
elimenohpee
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Homework Statement
Expand [tex] f(z) = (3z+1)/(15+2z-z^{2}) [/tex] at z=1 and find the circle of convergence.
Homework Equations
The Attempt at a Solution
I think this is pretty straight forward, but I want to make sure I'm doing everything correctly. I used a power series representation to find the circle of convergence, and expanded the function using the taylor series evaluated at z=1.
[tex] f(z) = (3z+1)/(15+2z-z^{2})
= -1/3 (1 / (1 + z/3)) + 2/5(1 / (1 - (z/5))
= -1/3\sum(-1)^{n} (z/3)^{n} + 2/5\sum (z/5)^{n} , |z|< 3 [/tex]
circle of convergence is then |z| < 3
I worked out the taylor series, and it matched with wolfram alpha here:
http://www.wolframalpha.com/input/?i=taylor+series+%283z%2B1%29%2F%2815%2B2z-z^2%29++at+z%3D1
Does everything look correct?