Calculating Clay's Acceleration: 12.0 m Fall

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To calculate the average acceleration of the clay after its 12.0 m fall, first determine the final speed upon impact using the equation v^2 = u^2 + 2gh. The initial speed (u) is zero, as the clay starts from rest, and g is the acceleration due to gravity. After finding the impact speed, use the contact time of 22.0 ms to calculate average acceleration, which is defined as the change in velocity over time. The discussion emphasizes understanding the relationship between the fall and the subsequent stopping time to solve the problem effectively. Accurate calculations will yield the average acceleration during the clay's contact with the ground.
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Homework Statement



A ball of moist clay falls 12.0 m to the ground. It is in contact with the ground for 22.0 ms before stopping.
(a) What is the average acceleration of the clay during the time it is in contact with the ground? (Treat the ball as a particle.)

Homework Equations


v^2 = u^2 + 2gh
v=final speed
u= initial speed

The Attempt at a Solution


I'mm not sure where to start this, as I don't think it is asking about the whole thing, but the 22 ms? I'm lost here.
 
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Ok, well first you could figure out how fast the ball is going when it hits the ground.

The next step is to ask yourself what the definition of average acceleration is and see if you have all the information you need to solve for it.
 
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