Calculating Common Velocity of Two Identical Blocks After Collision

AI Thread Summary
The problem involves two identical blocks with initial velocities of 3v and 2v colliding and moving together afterward. Using the conservation of momentum, the equation set up is 3mv + 2mv = 2mv', leading to a calculated common velocity of v' = 2.5v. However, there is a discrepancy as the provided answer is 1.5v. The calculations suggest that, based on the given information, the correct common velocity should indeed be 2.5v. The discussion highlights the importance of verifying the application of conservation of momentum in collision problems.
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Homework Statement


Two identical blocks of the same mass travel at velocities of 3v and 2v on a smooth surface as shown (same direction).
Two blocks move together after collision. What is their common velocity?

Homework Equations


Conservation of momentum

The Attempt at a Solution


Let v' be the common velocity.

3mv+2mv = 2mv'
v'= 2.5v

Therefore the veloctiy is 2.5v. Answer given is 1.5v.
 
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From the information given the answer should be 2.5 v.
 
Thank you
 

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