Calculating Constant Acceleration for a Cessna Aircraft Takeoff

AI Thread Summary
To calculate the minimum constant acceleration required for a Cessna aircraft to take off after a 250 m run, the liftoff speed of 120 km/h must first be converted to 33.33 m/s. The correct formula for constant acceleration can be applied using the equation v^2 = u + 2as, where v is the final velocity, u is the initial velocity (0), a is acceleration, and s is distance. After correcting the initial calculations, the necessary acceleration can be determined. The discussion highlights the importance of accurate unit conversion in solving physics problems related to aircraft takeoff.
nbroyle1
Messages
43
Reaction score
0
A Cessna aircraft has a liftoff speed of 120 km/h.

(a) What minimum constant acceleration does the aircraft require if it is to be airborne after a takeoff run of 250 m?
(b) How long does it take the aircraft to become airborne?

I tried using an equation for constant acceleration and plugged in: .277^2=0+2a(250). When I solved for a I got .000153 and it was incorrect. any suggestions?
 
Physics news on Phys.org
nbroyle1 said:
A Cessna aircraft has a liftoff speed of 120 km/h.

(a) What minimum constant acceleration does the aircraft require if it is to be airborne after a takeoff run of 250 m?
(b) How long does it take the aircraft to become airborne?

I tried using an equation for constant acceleration and plugged in: .277^2=0+2a(250). When I solved for a I got .000153 and it was incorrect. any suggestions?
Where did the "0.277" figure come from?

(Edit: And does 27.7 centimeters per second even sound like a reasonable velocity for the liftoff speed of a Cessna aircraft?)
 
After I converted the kilometers per hour to meters per second
 
nbroyle1 said:
After I converted the kilometers per hour to meters per second
You might want to try that calculation again. :smile:
 
thats my problem it should be 44.44m/s
 
thanks
 
nbroyle1 said:
thats my problem it should be 44.44m/s
Ummm, :rolleyes: Try that one more time. :smile:
 
i meant 33.33m/s haha
 
nbroyle1 said:
i meant 33.33m/s haha
That sounds better. :approve:
 
Back
Top