Calculating current through solenoid?

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To calculate the current in a solenoid using a bar magnet, Faraday's law is applicable, specifically the equation E=N(dphi/dt). Moving the bar magnet towards the solenoid induces a voltage, which can be measured with a voltmeter or multimeter, indicating a change in magnetic flux. The magnetic field of the bar magnet can be expressed as B=(μ₀/4π)(2m/r³), where m is the magnetic dipole moment and r is the distance from the midpoint. The dipole moment m is calculated as m=n(2L)I(πa²), with L being the length from the midpoint to one end and a the radius. Understanding these relationships allows for the determination of current in the solenoid based on the induced voltage.
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Not for a class or anything, just out of curiosity, how would you calculate the current in a solenoid, not given a magnetic field, but just using a bar magnet? I know it will just be some form of Faraday's law. E=N(dphi/dt). Maybe not. I'm imagining all I'm really missing is how to calculate the magnetic field of the magnet. Thanks.
 
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Take the solenoid and connect a voltmeter or multimeter across it. Move the barmagnet towards the solenoid and there should be a deflection in the voltmeter because ##\phi## changes when you keep moving the barmagnet.
or as you know, the bar magnet is also like a solenoid. The expression for magneticfield for barmagnet along axis is $$B=\frac{\mu_0}{4\pi}\frac{2m}{r^3}$$
 
So, just a little clarification, I did a little research online, is M the magnetic strength of each pole and r, I take it is the distance?

Thanks btw.
 
M is the magnetic fipole moment. Here, ##m=n(2L)I(\pi a^2)##
L is the length from midpoint to one end and 'a' is the radius. 'r' is the distance from midpoint to any point along the axis.
 
Awesome. Thank you
 
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