Calculating Deceleration and Force: Car and Trailer Braking Forces

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The discussion focuses on calculating the deceleration and forces involved when a car and trailer combination brakes. Given the car's mass of 1200 kg and the trailer's mass of 1050 kg, with braking forces of 4500 N and 3600 N, the deceleration of the system is determined to be 3.6 m/s². The horizontal force exerted by the trailer on the car is calculated to be 180 N. The calculations utilize the equations of motion and force diagrams to analyze the system's dynamics. This analysis provides insight into the braking forces acting on the combined vehicle system.
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A car of 1200 kg pull a trailer of 1050 kg. The set is moving at 90 km/h suddenly suffers the action of the brakes. Knowing that the forces of officers in the car brakes on the trailer and worth 4500N and 3600N, respectively, determine (a) the deceleration of the joint and (b) the horizontal component of force exerted by the trailer on the car

I think:

Car

ZFx = mc . a
-Ftc = mc . a

Trailer

ZFx = mt . a
Ftc = mt . a


But not possible to calculate
 
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Apprentice123 said:
A car of 1200 kg pull a trailer of 1050 kg. The set is moving at 90 km/h suddenly suffers the action of the brakes. Knowing that the forces of officers in the car brakes on the trailer and worth 4500N and 3600N, respectively, determine (a) the deceleration of the joint and (b) the horizontal component of force exerted by the trailer on the car

I think:
Car
ZFx = mc . a
-Ftc = mc . a

Trailer
ZFx = mt . a
Ftc = mt . a

But not possible to calculate

What is the deceleration of the combined system?

∑F = (∑m)*a

a = ∑F/∑m

Then, knowing the deceleration of the whole, draw a force diagram to figure the forces between the parts.
 
LowlyPion said:
What is the deceleration of the combined system?

∑F = (∑m)*a

a = ∑F/∑m

Then, knowing the deceleration of the whole, draw a force diagram to figure the forces between the parts.

Thank you.

a = (4500+3600)/(1200+1050) = 3,6 m/s^2

Break + F = mB . a
F = (1050 x 3,6) - 3600
F = 180 N
 
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