Calculating Deceleration on an Uphill Road

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To calculate the deceleration of a car on a 10° uphill incline, it is essential to consider both the frictional force and the gravitational component acting against the car's motion. The initial scenario on a level road allows for a deceleration of -5.00 m/s² due to friction alone. On the incline, the gravitational force adds complexity, requiring the use of Newton's second law (F = ma) to determine the net force and resulting deceleration. Visualizing the forces with a diagram can clarify the interactions at play. Understanding these principles will help in solving the problem effectively.
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This is the first time I have encountered a problem like this, and have no idea how to set it up, let alone solve it. Any help would be great.

Homework Statement



A car can decelerate at -5.00 m/s2 without skidding when coming to rest on a level road. What would be the magnitude of its deceleration if the road were inclined at 10° uphill? Assume the same static friction coefficient.
__________m/s2


Homework Equations





The Attempt at a Solution

 
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It looks like in the first scenario friction is providing the decelerating force while in the second scenario both friction and a component of the force of gravity are slowing the car down.

You can solve for the coefficient of static friction when the car is simply decelerating on a level rode (mass will cancel out so you do not need to know the car's mass) and use it to solve the net force on the car that is on the incline. (which then can be used to find the acceleration using Newton's second F = ma)
 
I'm still confused, and have no idea what I'm doing.
 
lokal704 said:
I'm still confused, and have no idea what I'm doing.

Try drawing a diagram of all the forces acting on the car in both examples. There should only be two - gravity and braking force (friction). Consider the angles the forces act on the car in each example.

Once you have that, see if MATdaveLACK's post will make more sense.
 
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