On a level road a motorcycle slows down with an acceleration of -3.40 m/s^2. Calculate the value of its acceleration when the road goes up hill 15 degrees.
Fnet = MA[/B]
The Attempt at a Solution
I tried setting up a system of equations and made friction equal.[/B]
Level road: friction force = ma
Inclined road: friction + wsin(theta) = ma2
Ma = ma2 - mgsin(theta)
A = a2 - gsin(theta)
A2 = A + gsin(theta)
A2 = -3.40 + (-9.8)(sin15)
But the answer isn't -5.94, so I don't know what I'm doing wrong. Thanks.