Calculating displacement on a v-t graph?

AI Thread Summary
To calculate displacement from a velocity-time graph, it's essential to find the total area under the curve, which includes both the triangular and rectangular sections. The formula BxH/2 applies only to right triangles, so it's crucial to account for any additional shapes present. In this case, the area of the rectangle beneath the triangle must also be included to reach the correct displacement value. The expected answer is 21,800, which suggests that the rectangle's area is significant in this calculation. Accurately combining these areas will yield the correct displacement.
aaquib
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Homework Statement



Im trying to get the displacement of a position on the graph with the following

point 1: (600, -75)
point 2: (720, -140)

Now usually I use BxH/2, because it's a triangle, but I can't really get it for this. The answer shows 21 800. I've tried everything in my power and can not get 21800. Any suggestions?


Thanks
Aaquib
 
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What kind of graph is this? (position vs time, velocity vs time, ect)
 
hunter151 said:
What kind of graph is this? (position vs time, velocity vs time, ect)

Sorry for not including it, but its a velocity time graph.
 
find the area of the graph
 
o..hmm did not see ur whole post
 
the BxH/2 only works for right triangles
 
Charlie_russo said:
the BxH/2 only works for right triangles

No, its a general formula for any triangle's area.

For this problem, you have only calculated the area of the triangle and forgetting the area of the rectangle underneath the triangle on the graph.

You have only got the area for this part of the graph:

http://img504.imageshack.us/img504/6357/graphzr3.jpg
 
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