Calculating displacement on a v-t graph?

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Homework Help Overview

The discussion revolves around calculating displacement from a velocity-time graph using specific points on the graph. The original poster attempts to apply the area formula for triangles to find the displacement but encounters difficulties in achieving the expected result.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the type of graph involved and question the original poster's method of calculating area. There is mention of needing to consider both triangular and rectangular areas for accurate displacement calculation.

Discussion Status

The discussion is ongoing, with participants providing insights into the correct approach for calculating the area under the curve of the graph. There is no explicit consensus yet, but some guidance has been offered regarding the need to account for different shapes in the area calculation.

Contextual Notes

Participants note that the graph in question is a velocity-time graph, which influences the method of calculating displacement. There is also a suggestion that the original poster may have overlooked certain areas in their calculations.

aaquib
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Homework Statement



Im trying to get the displacement of a position on the graph with the following

point 1: (600, -75)
point 2: (720, -140)

Now usually I use BxH/2, because it's a triangle, but I can't really get it for this. The answer shows 21 800. I've tried everything in my power and can not get 21800. Any suggestions?


Thanks
Aaquib
 
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What kind of graph is this? (position vs time, velocity vs time, ect)
 
hunter151 said:
What kind of graph is this? (position vs time, velocity vs time, ect)

Sorry for not including it, but its a velocity time graph.
 
find the area of the graph
 
o..hmm did not see ur whole post
 
the BxH/2 only works for right triangles
 
Charlie_russo said:
the BxH/2 only works for right triangles

No, its a general formula for any triangle's area.

For this problem, you have only calculated the area of the triangle and forgetting the area of the rectangle underneath the triangle on the graph.

You have only got the area for this part of the graph:

http://img504.imageshack.us/img504/6357/graphzr3.jpg
 
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