hunter151 said:What kind of graph is this? (position vs time, velocity vs time, ect)
Charlie_russo said:the BxH/2 only works for right triangles
Displacement on a v-t (velocity-time) graph measures the change in position of an object over a specific time interval. It is represented by the slope of the line on the graph, with steeper slopes indicating larger displacements.
To calculate displacement from a v-t graph, you can use the formula: displacement = (final velocity - initial velocity) x time. This is equivalent to finding the area under the curve on the graph, which represents the change in position over time.
Displacement is typically measured in units of length, such as meters or kilometers, as it represents a change in position. However, it can also be measured in other units such as miles or feet depending on the context of the problem.
Yes, displacement can be negative on a v-t graph. This occurs when the object is moving in the negative direction (opposite to the positive direction on the graph) and its final position is less than its initial position.
Acceleration affects displacement on a v-t graph by changing the slope of the line. A positive acceleration will result in a steeper positive slope, indicating a larger displacement over time. A negative acceleration will result in a steeper negative slope, indicating a smaller displacement over time or even a change in direction.