Calculating Distance and Height of Ball w/ 18° Loft & 10.9s Air Time

AI Thread Summary
To calculate the distance and height of a ball hit with an 18° loft and an initial velocity of 18.5 m/s, the horizontal distance can be determined using the equation deltaX = Vx(deltaT), where Vx is the horizontal speed and deltaT is the time in the air (10.9 s). The vertical calculations utilize the same time, with the acceleration due to gravity (9.8 m/s²) affecting the ball's ascent and descent. The maximum height can be found by recognizing that the speed at the peak of the flight is zero, allowing for the use of initial vertical speed and acceleration to solve for height. The calculations involve breaking down the initial velocity into horizontal and vertical components. This approach effectively provides the required distance and maximum height of the ball.
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Homework Statement


If a wood with loft 18 degrees is used to hit a ball that is in the air for 10.9 s, calculate:
(a) The distance the ball travels if its intial velociity is 18.5 m/s.
(b) The maximum height of the ball


Homework Equations





The Attempt at a Solution

 
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@d@m said:

Homework Statement


If a wood with loft 18 degrees is used to hit a ball that is in the air for 10.9 s, calculate:
(a) The distance the ball travels if its intial velociity is 18.5 m/s.
(b) The maximum height of the ball


Homework Equations





The Attempt at a Solution


For a:
If you know the time in which the ball is in the air for you can easily find the horizontal range. You do this because you know the initial velocity, which is 18.5 m/s [18 deg above the horizontal]. You can calculate the horizontal speed, which is always constant in this case. Then use the equation deltaX=Vx(deltaT) to find the horizontal range...

For b:
Time is independent of the vertical and horizontal directions so you can use the same time in the vertical calculations... You know acceleration in the y direction (9.8), You know the initial speed in the y direction because you can easily calculate it... And if you want to know the maximum height of the ball you know that it's speed at the top of its flight will be 0... Now you have 3 pieces of info you can use to solve b...

Hope I helped...
 
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