Calculating Distance Traveled: Car Speed and Cliff Jump Duration

Thread starter antphany
Start date Oct 16, 2011
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To calculate the distance a car would land from the base of a cliff after driving off at 50 km/h for 10 seconds, the horizontal velocity remains constant due to zero acceleration in that direction. Using the formula for distance, d = vt, where v is the horizontal speed, the distance traveled can be determined. The car's speed converts to approximately 13.89 m/s, leading to a distance of about 138.9 meters. The vertical motion is independent and does not affect the horizontal distance traveled. Thus, the car would land approximately 138.9 meters from the base of the cliff.

Oct 16, 2011

antphany

Homework Statement

if a car drove off a cliff at 50km/h, how far wouuld it land from the base of the cliff if it was in the air for 10s

Homework Equations

not sure

The Attempt at a Solution

i used v=at
i rearrachnged that 2 v/t=a
then i choosed to use d=1/2xaxt^2

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Oct 16, 2011

SammyS

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There is zero acceleration in the horizontal direction. (The horizontal component of velocity doesn't change.)

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