Calculating Distance Traveled: Motion Exam Question Solution in 7.4 Seconds

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A cyclist traveling at 4.2 m/s accelerates at 1.1 m/s² for 7.4 seconds, resulting in a distance traveled of 61 meters. The correct formula to use is s(t) = (1/2)at² + v₀t + s₀, which accounts for both acceleration and initial velocity. The confusion arose from incorrectly squaring the entire acceleration term instead of just the time variable. Clarifying the relevant equations in the initial post could help others avoid similar mistakes. This discussion highlights the importance of proper formula application in motion calculations.
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1. A Cyclist traveling at a speed of 4.2 ms^-1 accelerates at 1.1 ms^-2 in a time of 7.4 seconds. What is the distance travelled?


2. Homework Equations ?



3. The Attempt at a Solution : The answer is 61m but i don't know how to get that answer
 
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I would expect you to have seen s(t)=\frac{1}{2}at^2+v_0t+s_0?
 
Yeh thanks i got it
 
When i was doing it i was squaring the whole of the at instead of just the t
 
I see. You should really put that in the relevant equation section, that way people reading this forum could have seen what went wrong right away.
 
Yh sorry this was my first post but thanks anyway
 

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