Calculating Distance Traveled on Incline with Kinetic Friction

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To calculate the distance traveled by a box sliding up a 12.0° incline with a coefficient of kinetic friction of 0.180 and an initial speed of 2.40 m/s, one must consider both the forces acting on the box and energy principles. The normal force balances the gravitational force's component perpendicular to the incline, while the frictional force opposes the motion, affecting the box's acceleration. Applying the work-energy theorem, the work done by friction equals the change in the box's mechanical energy, which includes both kinetic and potential energy. By resolving these forces and applying kinematic equations, the distance can be determined before the box comes to rest. Understanding these concepts is crucial for solving the problem accurately.
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A box is sliding up an incline that makes an angle of 12.0° with respect to the horizontal. The coefficient of kinetic friction between the box and the surface of the incline is 0.180. The initial speed of the box at the bottom of the incline is 2.40 m/s. How far does the box travel along the incline before coming to rest?

I don't even know where to start. I'm guessing I should use kinematics, but where does the coefficient of kinetic friction and the angle fit into those?
 
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Resolve the forces acting on the box along and normal to the plane. normal components will balance ( write the equation0 and tengential components will accelerates the box( write the equation)
Remamper friction is in against the motion.
 
Have you tried an energy consideration? That is the work done by the frictional force should be equal to the change in the mechanical energy (it's kinetic and potential energy) of the box (this is called the work-energy theorem in Physics).
 
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