- #1

Thewindyfan

- 68

- 19

## Homework Statement

Anna is driving from Champaign to Indianapolis on I-74. She passes the Prospect Ave. exit at noon and maintains a constant speed of 75 mph for the entire trip. Chuck is driving in the opposite direction. He passes the Brownsburg, IN exit at 12:30pm and maintains a constant speed of 65 mph all the way to Champaign. Assume that the Brownsburg and Prospect exits are 105 miles apart, and that the road is straight.

How far from the Prospect Ave. exit do Anna and Chuck pass each other? x =

## Homework Equations

Anna's position: 75t + 0

Chuck's position: -65t + 105

## The Attempt at a Solution

I came up with the two equations above and then set them equal to each other, getting 140t = 105 => t = .75 hours, which I plugged into Anna's position equation since it's asking how far away we are from her initial position and got 56.25, but when I enter my answer it reminded me that I forgot to account for the fact that Chuck leaves a half an hour later, and for the life of me I cannot remember how to account for that in my equation for chuck for some reason. That's what I need help with. Thanks!