Calculating dy/dx for Inverse Sine Functions

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Y= sin^(-1)⁡〖x+ sin^(-1)⁡√((1-x^2 ) 〗
Please show steps for it...
 
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Since this problem has nothing to do with "differential equations", I am moving it.
 
Prasad Nemade said:
Y= sin^(-1)⁡〖x+ sin^(-1)⁡√((1-x^2 ) 〗
Please show steps for it...
There are some funny looking symbols in there. I will assume that the function is
y= sin^{-1}(x+ sin^{-1}(\sqrt{1- x^2}))

Let u(x)= 1- x^2, v(u)= \sqrt{u}= u^{1/2}, and w(v)= sin^{-1}(v). Then use the chain rule.
 
Moderator's note:

This looks like homework, or at the very least a textbook-style problem. Even if it's for independent study and not assigned coursework, this thread should in the Homework & Coursework Questions forums.

I am moving it to the Calculus & Beyond homework forum. Please note that the usual rules for homework help are in effect.

EDIT: in case it isn't clear -- we should let the OP reply with an attempt at solving this before offering further help.
 
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There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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