Calculating eigenvalues and eigenvectors

James2012
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Homework Statement


I'm having a problem with a question. I need to find the transition matrix in the form
T=UAU^-1
where U=[V1 V2]

Homework Equations


T=UAU^-1
where U=[V1 V2]

The Attempt at a Solution



my original transition matrix is [0.9 0.002; 0.1 0.998]
from that i calculated the eigenvalues to be 0.898 and 1
which means A=[0.898 0;0 1]
i found the eigenvectors to be V1=[1;-1] and V2=[0.002;0.1]
subbing these into the equation above i end up with the original transition matrix, however the question says to make use of the result [0.02 0.707;0.9998 -0.707]^-1 = [0.9823 0.9823;1.3866 -0.0278]


which means they use different eigenvectors, but I am not sure how they got that
 
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I also get the same eigenvals as you but the same vectos as them.
 
Hi, How did you get to the eigenvectors?
i used the equation (A-lamdaI)v=0

then for 0.898 i get the follwing

[0.002 0.002;0.1 0.1][V1;V2]=[0;0]
therefore the eigenvector for 0.898 is [1;-1]
 
To solve this, I first used the units to work out that a= m* a/m, i.e. t=z/λ. This would allow you to determine the time duration within an interval section by section and then add this to the previous ones to obtain the age of the respective layer. However, this would require a constant thickness per year for each interval. However, since this is most likely not the case, my next consideration was that the age must be the integral of a 1/λ(z) function, which I cannot model.
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