ok i believe Cij is the component of the stiffness matrix as outlined above, there's no reall easy way to go through it... Cij is the ith row, jth component of thw stiffness matrix given in
http://www.efunda.com/formulae/solid_mechanics/mat_mechanics/hooke_isotropic.cfm
(a condensed matrix form of the full cijkl tensor)
i'm not too sure what C12 means, but in the matrix it relates the stress in the x dir'n to a normal strain in the y dir'n... so 1-3 represent normal stress/strain, 4-6 shear stress/strain..
then i think C11, C22, C33 will represent the longitudinal speeds (all same in isotropic)
while C44, C55, C66 will represnet the shear wave speeds (all same in isotropic)
from a bit of googling on elastic isotropic materials, to remember this stuff...
first shear velocity is relateable to the shear mdoulus
v_s = \sqrt{\frac{G}{\rho}}
The shear modulus is then relateable to young's modulus & poissons ratio by
G = \frac{E}{2(1+\nu)}}
now longitudinal velocity is relateable to young's modulus & poissons ratio by
v_s = \sqrt{\frac{E(1-\nu)}{\rho(1-2\nu)(1+\nu)}}
so you shold be able to solve for E & nu, knowing vp, vs & denisty & assuming linear elastic isotropic
this would then allow you to fill out the stiffness matrix as given... ie the Cij
note i think vp = sqrt(C11/rho) and vs = sqrt(C44/rho) which gives some cofidence that we're on the right track
anyway hope this of some help, if its introductory we may be deving into it a bit much...