Calculating Electric Field of Two Point Charges

AI Thread Summary
The discussion focuses on calculating the electric field generated by two point charges: -7e-6 C at (3 m, -2 m) and 12e-6 C at (1 m, 3 m). The user attempts to compute the electric field but seems to miscalculate the contributions from the charges, particularly using the wrong sign for one charge and failing to consider vector addition for the electric fields. The correct approach involves calculating the electric field contributions as vectors, taking into account both the magnitude and direction. The user is advised to clarify the specific point where the electric field is being evaluated and to ensure proper vector addition. Accurate calculations and vector components are essential for determining the resultant electric field.
Zvaigzdute
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Homework Statement



A point charge of -7e-6 C is located at x = 3 m, y = -2 m. A second point charge of 12e-6 C is located at x = 1 m, y = 3 m.

Homework Equations





The Attempt at a Solution



Dq1 = sqrt(20)
Dq2 = sqrt (13)

E1 + E2= k(-7e-6)/20 + k(-7e-6)/20 = 11444.96 N/C

What am I doing wrong?

And how to find the direction ?

 
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Hi *! :smile:

(have a square-root: √ and try using the X2 icon just above the Reply box :wink:)
Zvaigzdute said:
A point charge of -7e-6 C is located at x = 3 m, y = -2 m. A second point charge of 12e-6 C is located at x = 1 m, y = 3 m.
E1 + E2= k(-7e-6)/20 + k(-7e-6)/20 = 11444.96 N/C

(I assume you're trying to find the field at (-1,0)?)

i] One of those should be +12. :rolleyes:

ii] You must add these as vectors, so use x and y components. :wink:
 
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