Calculating Electric Force and Distance Between Two Charges

AI Thread Summary
The discussion centers on calculating the electric force and distance between two charges, q1 and q2, with given values and a force of 55μN acting on q1 from q2. The key point is that the force exerted by q1 on q2 is equal in magnitude but opposite in direction, remaining at 55μN. To find the distance between the charges, Coulomb's law is applied using the known force without adding forces together. The correct approach is to use the single force value of 55μN in the equation F = (k*q1*q2)/d^2 to solve for distance d. The clarification emphasizes that forces should not be combined, maintaining the integrity of Coulomb's law calculations.
shanie
Messages
23
Reaction score
0

Homework Statement


Two small charges q1 = +2.65 nC and q2=-4.75nC are at a certain distance from each other. Q1 is affected by a force of 55μN from q2.
a) how large is the force on q2? Draw a figure that shows the electric forces that work on q1 and q2.
b) determine the distance between the charges.


Homework Equations


a) coulomb's law: F= (k*qi*q2)/d^2
b) coulomb's law: F= (k*qi*q2)/d^2

The Attempt at a Solution


a)Now I know that these questions are generally rather simple and straightforward, but what I cannot understand is how I'm going to solve the problem with two unknowns (the force on q2 and the distance). Because I only have a set of data I cannot really make a simultaneous equation out of it. I tried using E=F/q for q2 but then I only get E for one of the charges.. so how would I go on from there? I already drew a picture showing the two attracting forces with arrows toward each other (as one charge is positive and the other one negative).
b) Once I find the force on q2, I just add the forces together and make them equal to F in coloumb's law.. right? So then I just rearrange the variables and solve for d?

I could really use some help, thanks!
 
Physics news on Phys.org
a) Think of Newton's laws. The answer is really simple when you see it.
 
Oh, you mean for every action there is an equal and opposite reaction? So if q2 works on q1 by 55μN, this means that q1 works on q2 by 55μN? So then in b) I just add them together to make 110μN, which I then plug into coulomb's law:

110 μN = (k*q1*q2)/d^2
And solve for d?
 
No, do not add the forces. Just use 55 uN for the force.

That equation gives the force F exerted by one charge on the other. They told you this force is 55 uN.
 
Oh, I see! Thanks :)
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanged mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top